Correct Answer: 15 mts.

A is Vasu's house

B is Ganesh's house

C is Bus stand

To find the distance AC

From \( \Large \triangle ABC,\ AC^{2} = BC^{2} - AC^{2} \)

= \( \Large 25^{2} - 20^{2} \)

=\( \Large \left(25+20\right) \left(25-20\right) \)

= \( \Large 45 \times 5 = 225 \)

\( \Large AC = \sqrt{225} = 15 \)

Ganapathy has to cover a distance of 15 mts. to come to Vasu's house.