>> Aptitude >> Discount

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Contents:

- Aptitude
- Approximation
- Average
- Boat and Stream
- Compound interest
- Discount
- Linear Equations
- Mensuration
- Mixture and Allegation
- Number series
- Number System
- Partnership
- Percentage
- Permutation and combination
- Pipes and Cisterns
- Probability
- Problem on ages
- Profit and Loss
- Ratio and Proportions
- Simple and compound interest
- Time and Distance
- Time and work
- Trains
- Unitary Method
- Word problems
- Work and Wages

1). On a 20% discount sale, an article costs 596. What was the original price of the article?
Let the original price of be x. | ||||

2). If an electricity bill is paid before due date, one gets a reduction of 4% on the amount of the bill. By paying the bill before due date, a person got a reduction of Rs.13. The amount of his electricity bill was
Let the amount of electricity bill = Rs.x | ||||

3). If on a marked price, the difference of selling prices with a discount of 30% and two successive discounts of 20% and 10% is Rs.72, then the marked price (in Rs.) is
Let the marked price = Rs.x | ||||

4). Two successive discounts of 20% and 20% are equivalent to a single discount of
Given, \( \Large r_{1} \) = 20% and \( \Large r_{2} \) = 20% | ||||

5). Two successive discounts of 20% and 5% are equivalent to a single discount of
Here, \( \Large r_{1} \) = 20% and \( \Large r_{2} \) = 5% | ||||

6). A shopkeeper earns a profit of 12% on Selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is
Let the CP of book = Rs.x Then, SP of book = \( \Large \frac{ \left(100+12\right) \times x }{100}=\frac{112x}{100} \) Now. the printed price = Rs.y Then, after discount, the SP = \( \Large \frac{ \left(100-10\right) \times y }{100}=\frac{90y}{100} \) Since, both SP are same. Then, \( \Large \frac{112x}{100} = \frac{90y}{100} = \frac{x}{y} = \frac{45}{56} \) = 45 : 56 | ||||

7). A manufacturer marked an article at Rs.50 and sold it allowing 20% discount. If his profit was 25%, then the cost price of the article was
Marked price of an article = Rs.50 | ||||

8). A seller marks his goods 30% above their cost price but allows 15% discount for cash payment. His percentage of profit When sold in cash, is
Let CP of the goods = Rs.x. | ||||

9). Successive discounts of 10%, 20% and 30% is equivalent to single discount of
Here \( \Large r_{1} \)= 10%, \( \Large r_{2} \) = 20% and \( \Large r_{3} \) =30% Therefore, Required discount = \( \Large \left[ 1- \left(1-\frac{r_{1}}{100}\right) \left(1-\frac{r_{2}}{100}\right) \left(1-\frac{r_{3}}{100}\right) \right] \times 100\% \) = \( \Large \left[ 1- \left(1-\frac{10}{100}\right) \left(1-\frac{20}{100}\right) \left(1-\frac{30}{100}\right) \right] \times 100\% \) = \( \Large \left(1-\frac{9}{10} \times \frac{4}{5} \times \frac{7}{100}\right) \times 100\% \) = \( \Large \left(1-0.504\right) \times 100\% \) = 49.6% | ||||

10). By selling an article at \( \Large \frac{3}{4} \)th of the marked price, there is a gain of 25%. The ratio of the marked price and the cost price is
Let MP of an article = Rs.x Therefore, SP of an article = Rs.\( \Large \frac{3}{4}x \) and CP of an article = \( \Large \frac{3x}{4} \times \frac{100}{100+25} \) = \( \Large \frac{3x}{4} \times \frac{100}{125}= Rs.\frac{3x}{5} \) Required ratio = \( \Large x : \frac{3x}{5} \) = 5 : 3 |