Any positive or negative number \( \Large \neq \) 0 will never have its square as zero or negative If k = \( \Large \frac{1}{2} \) Then \( \Large k^2 \) = \( \frac{1}{4}\) So \( \Large k^2 < k \) Hence \( \Large k^2 < k \) is true.
We know , \( \Large a^x.a^y = a^{x+y} \) = > \( \Large 3^4.3^3 = 3^{4+3} = 3^7 \)