Using Remainder theorem put \( \Large x^4 = -1\) in \( \Large x^{40} +2\) = > \( \Large \left( x^4 \right)^{10}\) + 2 = > \( \Large \left( -1 \right)^{10} \) +2 = > 1 + 2 = 3
Face value is the value of digit itself. Required face value = 6