>> Aptitude >> Simple and compound interest

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Contents:

- Aptitude
- Approximation
- Average
- Boat and Stream
- Compound interest
- Discount
- Linear Equations
- Mensuration
- Mixture and Allegation
- Number series
- Number System
- Partnership
- Percentage
- Permutation and combination
- Pipes and Cisterns
- Probability
- Problem on ages
- Profit and Loss
- Ratio and Proportions
- Simple and compound interest
- Time and Distance
- Time and work
- Trains
- Unitary Method
- Word problems
- Work and Wages

1). What would be the simple interest accrued in 4 yr on a principle of RS. 18440 at the rate 15% per annum?
Given, P = 18440, R = 15%, T =4 | ||||

2). Rakesh lent out RS. 8750 at 7% annual interest. Find the simple interest in 3 yr.
Given, P = RS. 8750, R =7%, T=3y | ||||

3). What will be simple interest for 1 yr and 4 months on a sum of RS. 25800 at the rate of 14% per annum?
Here, P = RS. 25800, R = 14% | ||||

4). The sum which amounts to RS. 364.80 in 8 yr at 3.5% simple interest per annum is
Given, t = 8 yr, r= 3.5%, A=Rs.364.80 | ||||

5). A sum of Rs. 2668 amounts to Rs. 4669 in 5yr at the rate of simple interest. Find the rate per cent.
Here, P = RS. 2668, T = 5yr, A = RS. 4669 | ||||

6). Find the difference in amount and principal for RS. 4000 at the rate of 5% annual interest in 4 yr.
The required difference in amount and principal is SI = A - P. Here, P = RS. 4000, R = 5%, T = 4 yr According to the formula, SI = \( \Large \frac{P\times R\times T}{100} \) = \( \Large \frac{4000\times 5\times 4}{100} \) =RS.800 | ||||

7). Kriya deposits an amount of RS. 65800 to obtain a simple interest at the rate of 14% per annum for 4 yr. What total amount will Kriya get at the end of 4 yr?
Here, P = RS. 65800, R = 14%, T = 4 yr Hence, SI = \( \Large \frac{65800\times 14\times 4}{100} \)= RS. 36848 Required amount = P + SI = 65800 + 36848 = RS. 102648 | ||||

8). A sum becomes its double in 10 yr. Find the annual rate of simple interest.
Let the sum be P. Then, after 10 yr Sum = 2P SI = 2P - P = P Now, SI=\( \Large \frac{P\times R\times T}{100} \)=> P=\( \Large \frac{P\times R\times 10}{100} \) R = 10% | ||||

9). A certain sum becomes 3 fold at 4% annual rate of interest. At what rate, it will become 6 fold?
Let the sum be P. Then, for 4% SI = (3P-P)=2P 2P = \( \Large \frac{P\times 4\times T}{100} \)=> 1=\( \Large \frac{2T}{100} \)=\( \Large \frac{T}{50} \) T = 50yr Again, for another rate (R), SI =(6P-P) =5P 5P = \( \Large \frac{P\times R\times 50}{100}=\frac{PR}{2} \) R = 10% | ||||

10). A sum becomes 6 fold at 5% per annum. At what rate, the sum becomes 12 fold?
SI at 5% = 6P-P=5P |