Correct Answer: x < y

I. \( \Large x^{2} \) + 11x + 30 = 0

=> \( \Large x^{2} \) + 6x + 5x + 30 = 0

=> x ( x + 6 ) + 5 ( x + 6 ) = 0

=> ( x + 5 ) ( x + 6 ) = 0

x = -5 or -6

II. \( \Large y^{2} \) + 7y + 12 = 0

=> \( \Large y^{2} \) + 4y + 3y + 12 = 0

=> y ( y + 4 ) + 3 ( y + 4 ) = 0

=> ( y + 3 ) ( y + 4 ) = 0

\( \Large \therefore \) y = -3 or -4

Clearly, x < y