In the following question two equations numbered I and II are given. You have to solve both the equations and -
I. \( \Large x^{2} \) + 11x + 30 = 0
II. \( \Large y^{2} \) + 7y +12 = 0
Correct Answer: Description for Correct answer:
I. \( \Large x^{2} \) + 11x + 30 = 0
=> \( \Large x^{2} \) + 6x + 5x + 30 = 0
=> x ( x + 6 ) + 5 ( x + 6 ) = 0
=> ( x + 5 ) ( x + 6 ) = 0
x = -5 or -6
II. \( \Large y^{2} \) + 7y + 12 = 0
=> \( \Large y^{2} \) + 4y + 3y + 12 = 0
=> y ( y + 4 ) + 3 ( y + 4 ) = 0
=> ( y + 3 ) ( y + 4 ) = 0
\( \Large \therefore \) y = -3 or -4
Clearly, x < y
Part of solved Linear Equations questions and answers :
>> Aptitude >> Linear Equations