Topics
In the following question two equations numbered I and II are given. You have to solve both the equations and -
I. \( \Large \frac{3}{\sqrt{x}} + \frac{4}{\sqrt{x}} \) = \( \Large \sqrt{x} \)
II. \( \Large y^{3} - \frac{(7)^{\frac{7}{2}}}{\sqrt{y}} \) = 0
|
A) x > y |
|
B) x \( \Large \geq \) y |
|
C) x < y |
|
D) x = y or the relationship cannot be established |
Correct Answer:
| D) x = y or the relationship cannot be established |
Description for Correct answer:
I. \( \Large \frac{3}{\sqrt{x}} + \frac{4}{\sqrt{x}} = \sqrt{x} \)
=> 3 + 4 = x
=> x = 7
II. \( \Large y^{3} - \frac{(7)^{\frac{7}{2}}}{\sqrt{y}} = 0 \)
\( \Large y^{3 + \frac{1}{2}} - (7)^{\frac{7}{2}} \) = 0
=> \( \Large y^{\frac{7}{2}} = 7^{\frac{7}{2}} \)
=> y = 7
I. \( \Large \frac{3}{\sqrt{x}} + \frac{4}{\sqrt{x}} = \sqrt{x} \)
=> 3 + 4 = x
=> x = 7
II. \( \Large y^{3} - \frac{(7)^{\frac{7}{2}}}{\sqrt{y}} = 0 \)
\( \Large y^{3 + \frac{1}{2}} - (7)^{\frac{7}{2}} \) = 0
=> \( \Large y^{\frac{7}{2}} = 7^{\frac{7}{2}} \)
=> y = 7
Part of solved Linear Equations questions and answers : >> Aptitude >> Linear Equations
Comments
Similar Questions
