Let PQ be the plane which passes through middle point O of the axis AO of the cont(A,BC).
Let r be the radius of the cone (A, PQ) and h its height. Then, from geometry, radius of the cone (A,BC) is 2r and its height is 2h.
Volume of the cone (A, PQ) = \( \Large\frac{1}{3} \pi r^2 h \)
Volume of the cone (A,B,C)
= \( \Large\frac{1}{3} \pi r^2.(2r)^2(2h)\)
= \( \Large\frac{8}{3} \pi r^2 h\)
Volume of the portion (PB, OC) = Volume of the cone (A, BC) - Volume of the cone (A, PQ)
= \( \Large\frac{8}{3} \pi r^2 h\) - \( \large\frac{1}{3} \pi r^2 h\)
= \( \Large\frac{7}{3} \pi r^2 h\)
Required ratio = \( \Large\frac{ \Large\frac{1}{3} \pi r^2 h }{\large\frac{7}{3} \pi r^2 h} \)
= 1/ 7 = 1 : 7