Let the number of students be 3x, 4x and 5x.
Then (3x + 15) : (4x + 15) : (5x +15) = 6 : 7 : 8
\( \Large \frac{3x + 15}{6} = \frac{4x + 15}{7} \)
= \( \Large\frac{5x + 15}{8} \)
= > 7(3x +15) = 6(4x + 15)
X = 5
Total number of students before increase = >12x = 60