Time and Distance Questions and answers

Topics

General Knowledge
General Science
General English
Aptitude
General Computer Science
General Intellingence and Reasoning
Current Affairs
Exams
Elementary Mathematics
English Literature

Aptitude

71). A person goes from one point to another point with a speed of 5 km/h and comes back to starting point with a speed of 3 km/h. Find the average speed for the whole journey.

A). 4.5 km/h

B). 4 km/h

C). 4.25 km/h

D). 3.75 km/h

View Answer

72). A bus travels at the rate of 54 km/h without stoppages and it travels at 45 km/h with stoppages. How many minutes does the bus stop on an average per hour?

A). 8 min

B). 10 min

C). 12 min

D). 4 min

View Answer

73). A bus covers a certain distance in 16 h. It covers half the distance at 40 km/h and the rest at 60 km/h. Find the length of the journey.

A). 520 km

B). 448 km

C). 384 km

D). 768 km

View Answer

Correct Answer: 768 km

Let the total distance covered = x

= Length of journey

According to the question,

\( \Large \left(\frac{x}{2} \times \frac{1}{40}\right) = \left(\frac{x}{2} \times \frac{1}{60}\right) = 16 \)

\( \Large \frac{x}{80} + \frac{x}{120} = 16 \)

\( \Large \frac{3x+2x}{240} = 16 \)

\( \Large 5x = 16 \times 240 \)

\( \Large x = \frac{16 \times 240}{5} = 16 \times 48 = 768 km \)

74). The ratio between the rates of travelling of A and B is 2 : 3 and therefore A takes 20 min more than time taken by B to reach a destination. If A had walked at double the speed, how long would he have taken to cover the distance?

A). 30 min

B). 35 min

C). 20 min

D). 45 min

View Answer

Correct Answer: 30 min

We know that speed is inversely proportional to time. Therefore,

Time taken by A : Time taken by B =

Let B takes x min. Then, A takes (x + 20) min.

Therefore, \( \Large \left(x+20\right) : x = \frac{1}{2}:\frac{1}{3}=3:2 \)

\( \Large \frac{x+20}{x}=\frac{3}{2} => 2x+40 = 3x\)

\( \Large x = 40 \)

\( \Large \left(x+20\right) \)

\( \Large or \left(40+20\right) = 60 min \)

Therefore,

At double the speed, A would have covered it in 30 min.

75). A car travels a distance of 75 km at the speed of 25 km/h. It covers the next 25 km of its journey at the speed of 5 km/h and the last 50 km of its journey at the speed of 25 km/h. What is the average speed of the car?

A). 40 km/h

B). 25 km/h

C). 15 km/h

D). 12.5 km/h

View Answer

Correct Answer: 15 km/h

Time taken to over first 75 km = \( \Large \frac{75}{25} = 3 h \)

Time taken to cover next 25 km = \( \Large \frac{25}{5} = 5 h \)

Time taken to cover last 50 km journey = \( \Large \frac{50}{25} = 2 h \)

Total distance = 75+25+50 = 150 km

Total time taken =3+5+2 = 10 h

Therefore, Required average speed

= \( \Large \frac{Total \ distance}{Total \ time \ taken}=\frac{150}{10}=15 km/h \)

76). If you travel 39 km at a speed of 26 km/h, another 39 km at a speed of 39 km/h and again 39 km at a speed of 52 km/h, what is your average speed for the entire journey?

A). 39 km/h

B). 37 km/h

C). 33.33 km/h

D). 36 km/h

View Answer

Correct Answer: 36 km/h

Required average speed = \( \Large \frac{Total \ distance \ covered}{Total \ time \ taken} \)

\( \Large = \frac{3 \times 39}{ \Large \frac{36}{26}+\frac{39}{39}+\frac{39}{52}} \)

\( \Large = \frac{3 \times 13}{ \Large \frac{1}{2}+\frac{1}{3}+\frac{1}{4}} \)

\( \Large = \frac{3 \times 13 \times 12}{13} = 36 km/h \)

77). Dalbir Singh, a policeman, is 114 in behind a thief. Dalbir Singh runs 21 in and the thief 15 in a minute. In what time will Dalbir Singh catch the thief?

A). 19 min

B). 16 min

C). 21 min

D). 23 min

View Answer

78). A person covers half of his journey at 40km/h, one-third at 60 km/h and rest of journey at 30 km/h. Find his average speed for the whole journey.

A). 45 km/h

B). 42.35 km/h

C). 50 km/h

D). 40 km/h

View Answer

Correct Answer: 42.35 km/h

Here. the person covers ½ of his Journey at 40 km/h, 1/3 at 60 km/h and rest

\( \Large \left(1 - \frac{1}{2} - \frac{1}{3} = \frac{1}{6}\right) \ at \ 30 km/h \)

\( \Large = \frac{1}{ \Large \frac{1}{2 \times 40}+\frac{1}{3 \times 60}+\frac{1}{6 \times 30}} \)

\( \Large\frac{1}{ \Large \frac{1}{80}+\frac{1}{180}+\frac{1}{180}} \)

\( \Large \frac{720}{9+4+4} = \frac{720}{17} = 42.35 km/h \)

79). A boy walking at a speed of 15 kin/b reaches his school 20 min late. Next time he increases his speed by 5 km/h but still he late by 5 min. Find the distance of the school from his home.

A). 5 km

B). 10 km

C). 15 km

D). 20 km

View Answer

Correct Answer: 15 km

Let the distane = x

Here, the differe4nce in time

= 20 - 5 = 15 min

= 15/60 = 1/4 h

Speed during next journey = 15 +5 = 20 km/h

According to the question,

\( \Large \frac{x}{15} - \frac{x}{20} = \frac{1}{4} \)

\( \Large \frac{4x-3x}{60} = \frac{1}{4} \)

\( \Large x = \frac{60}{4} = 15 \)

\( \Large x = 15 km \)

80). Two cars A and B start simultaneously from a certain place at the speed of 30 km/h and 45 km/h, respectively. The car B reaches the destination 2 h earlier than A, What is the distance between the starting point and destination?

A). 90 km

B). 180 km

C). 270 km

D). 360 km

View Answer

Correct Answer: 180 km

Let the time taken by car B to reach destination is x h.

So, the time taken by r A to reach destination is (x + 2) h.

Now, \( \Large S_{1}T_{1} = S_{2}T_{2} \)

\( \Large = 30 \times \left(x+2\right) = 45 \times x \)

\( \Large 30x + 6 = 45x \)

\( \Large 15x = 60 \)

\( \Large x = 4 h \)

Therefore, Now, distance between starting point and destination

\( \Large = S_{2}T_{2} = 45 \times 4 = 180 km \)

5	6	7	8	9	10	11

Go to :

Total Pages : 36