Directions (31-35) : Study the following graph carefully and answer the questions that follow :
The graph given below represents the number of users of two broadband services A and B across 5 cities P, Q, R, S and T.
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31). What is the total number of users of brand B across all give cities together ?
A). 2700 |
B). 3000 |
C). 3100 |
D). 2900 |
E). 3200 |
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32). The number of uses of brand A in city T is what percent of the number of users of brand B in city Q ?
A). 150 |
B). 110 |
C). 140 |
D). 160 |
E). 120 |
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33). What is the average number of users of brand A across all five Cities together ?
A). 560 |
B). 570 |
C). 580 |
D). 590 |
E). 550 |
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34). What is the difference between the total number of users of Brand A and B together in city R and the total number ofusers ofbrand A and B together in city P ?
A). 170 |
B). 140 |
C). 130 |
D). 150 |
E). 160 |
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35). What is the respective ratio of the number users of brand A in city P to the number of users of brand B in city S?
A). 5:7 |
B). 4:7 |
C). 2:5 |
D). 3:4 |
E). 5:6 |
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Directions (36-40) : What approximate value should come in place of the question mark (?) in the given questions ? (Note : You are not expected to calculate the exact Value)
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36). \( \large \sqrt{1230} \) + \( \large \sqrt{4230} \) = ?
A). 50 |
B). 200 |
C). 100 |
D). 150 |
E). 250 |
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37). 7\( \Large \frac{3}{11} \) \( \Large \times \) 626 - 7\( \Large \frac{2}{3} \) = ?
A). 4445 |
B). 4545 |
C). 4495 |
D). 4595 |
E). 4515 |
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38). 49% of 5051 - \( \Large \frac{3}{7} \)th of 999 = ?
A). 2145 |
B). 2045 |
C). 1945 |
D). 1905 |
E). 2165 |
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39). 4329 + 19 + 6464 + 13 = ?
A). 725 |
B). 625 |
C). 925 |
D). 525 |
E). 825 |
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40). \( \large 4.012^{3} \) + \( \large (29.997^{2} \) = ?
A). 1025 |
B). 965 |
C). 745 |
D). 765 |
E). 305 |
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