Exams >> Bank Exams >> SBI Associates Clerk

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Contents:

SBI Associates clerk consists of below sections.

- Reasoning ability(Question No: 1 - 40)
- General English(Question No: 41 - 80)
- Quantitative Aptitude(Question No: 81 - 120)
- Computer Knowledge(Question No: 121 - 160)

Correct Answer: 479
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82). 154 158 185 201 326 ?
Correct Answer: 362
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83). 3 27 189 945 ? 2835
Correct Answer: 2835
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84). 721 361 181 91 46 ?
Correct Answer: 23.5
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85). 2 7 26 101 400 ?
Correct Answer: 1595
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86). Present ages of Neha and Rashmi are in the ration of 7 : 8 respectively. Six years hence, the ration of their ages will become 9 : 10 respectively. What is the Rashmis present age?(In years).
According to question, \( \frac{7x+6}{8X+6} = \frac{9}{10} \) 70x + 60 = 72x + 54 2x = 6 x = 3 | ||||||

87). The compound interest(compounded -annually) on a certain sum of money at the rate of 20 p.c.p.a. for 2 years is Rs.5,632/-. What is the simple interest on the same sum of money at the rate of 12 p.c.p.a. for 3 years ?
Let the Principal be = Rs.x According to question, \( 5632 = x \left[ 1+\frac{20}{100} \right]^{2} - x \) \( 5632 = x\left[ \frac{36}{25}-1 \right] \) \( x = \frac{5632 \times 25}{11} \) \( x = Rs.12,800/- \) \( \frac{12800 \times 12 \times 3}{100} = Rs.4,608/- \) | ||||||

88). A and B started a business together by investing Rs.10,400/- and Rs.14,300/- respectively. After 4 months C joined them with an amount of Rs.9,100/-. If they earned on annual profit of Rs.11360 What is the C's share of profit?
A : B : C = \( 10400 \times 12 : 14300 \times 12 : 9100 \times 8 \) \( = 1248 : 1716 : 728 = 312 : 429 : 182 \) \( = 11360 \times \frac{182}{ \left(312+429+182\right) } \) \( = Rs.2,240/- \) | ||||||

89). The present population of village P is 2 times the population of village Q an year ago. If after a year, the population of village Q will be 3528 increasing at a constant rate of 20% every year, what is the present population of village P?
An year ago, let the population of village Q = x Then, the presenet population of village P = 2x Accordig to question, \( 3528 = x \times \frac{120}{100} \times \frac{120}{100} \) \( x = 2450 \) \( = 2 \times 2450 = 4900 \) | ||||||

90). The sum of two numbers is 506. If the second number is 5/18th of the first number. What is the difference between the 4/9 of the first number and 2/11 of the second number ?
Let the first number be x. Thereforer, second number = \( \frac{15}{18}x \) According to question, \( x + \frac{5}{18} = 506 \) \( \frac{23}{18}x = 506 \) \( x = 396 \) Therefore, sercond number = 110 Required difference = \( \frac{4}{9} \times 396 - \frac{2}{11} \times 110 \) \( = 176 - 20 = 156 \) |