51). Simplify:-\( \Large \left[ 64^{\frac{2}{3}} \times 2^{-2}\div8^{0} \right]^{\frac{1}{2}} \)
A). 0 |
B). 1 |
C). 2 |
D). \( \Large \frac{1}{2} \) |
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52). The value of \( \Large \frac{1}{\sqrt{ \left(12-\sqrt{140}\right) }}-\frac{1}{\sqrt{8-\sqrt{60}}}-\frac{2}{\sqrt{10+\sqrt{84}}} \) is:
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53). The value of \( \Large \sqrt{11+2\sqrt{30}}-\frac{1}{\sqrt{11+2\sqrt{30}}} \) is:
A). \( \Large 2\sqrt{5} \) |
B). \( \Large 2\sqrt{6} \) |
C). \( \Large 1+\sqrt{6} \) |
D). \( \Large 1+\sqrt{5} \) |
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54). Simplify \( \Large \frac{ \left(1.5\right)^{3}+ \left(4.7\right)^{3}+ \left(3.8\right)^{3} -3 \times 1.5 \times 4.7 \times 3.8 }{ \left(1.5\right)^{2}+ \left(4.7\right)^{2} + \left(3.8\right)^{2}-1.5 \times 4.7+4.7 \times 3.8-3.8 \times 1.5 } \)
A). 0 |
B). 1 |
C). 10 |
D). 30 |
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55). Simplify: \( \Large \frac{ \left(6.25\right)^{\frac{1}{2}} \left(0.0144\right)^{\frac{1}{2}}+1 }{ \left(0.027\right)^{\frac{1}{3}} \times \left(81\right)^{\frac{1}{4}} } \)
A). 0.14 |
B). 1.4 |
C). 1 |
D). 1.44.... |
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56). Simplify: \( \Large\frac{0.41 \times 0.41 \times 0.41+0.69 \times 0.69 \times 0.69}{0.41 \times 0.41-0.41 \times 0.69+0.69+0.69} \)
A). 0.28 |
B). 1.41 |
C). 1.1 |
D). 2.8 |
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57). Which of the following number is the least?
\( \Large \left(0.5\right)^{2},\sqrt{0.49},\sqrt[3]{0.008},0.23 \)
A). \( \Large \left(0.5\right)^{2} \) |
B). \( \Large \sqrt{0.49} \) |
C). \( \Large \sqrt[3]{0.008} \) |
D). 0.23 |
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58). If \( \Large 3^{10 \times 27^{2}} = 9^{2} \times 3^{n} \) then thevalue of n is:
A). 10 |
B). 12 |
C). 15 |
D). 30 |
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59). The greatest among the numbers \( \Large \left(2.89\right)^{0.5},2- \left(0.5\right)^{2},1+\frac{0.5}{1-\frac{1}{2}} ,\sqrt{3} \) is :
A). \( \Large \left(2.89\right)^{0.5}\) |
B). \( \Large 2- \left(0.5\right)^{2}\) |
C). \( \Large 1+\frac{0.5}{1-\frac{1}{2}} \) |
D). \( \Large \sqrt{3} \) |
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60). Among \( \Large \sqrt{2},\sqrt[3]{3},\sqrt[4]{5},\sqrt[3]{2} \) which one is greates?
A). \( \Large \sqrt[4]{5} \) |
B). \( \Large \sqrt{2} \) |
C). \( \Large \sqrt[3]{3} \) |
D). \( \Large \sqrt[3]{2} \) |
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