Let \( \Large a=2x-3y, b=3y-5z,\ and\ c=5z-2x \)
\( \Large \therefore a+b+c = 2x-3y+3y-5z+5z-2x = 0 \)
Now, \( \Large a^{3}+b^{3}+c^{3}=3abc \)
\( \Large \therefore \left(2x-3y\right)^{3}+ \left(3y-5z\right)^{3}+ \left(5z-2x\right)^{3} \)
\( \Large = 3 \left(2x-3y\right) \left(3y-5z\right) \left(5z-2x\right) \)