The time taken by the boat to cover a distance of 'D 56' km upstream is half of that taken by it to cover a distance of 'D' km downstream. The respective ratio between the speed of the boat downstream and that upstream is 5 :3. If the time taken to cover 'D32' km upstream is 4 hours, what is the speed of water current ? (in km/h)
Correct Answer: Description for Correct answer:
Let the speed of boat in upstream = 3x
Speed of boat in downstream = 5x
according to question,
\( \Large \frac{D - 56}{3x} \) = \( \Large \frac{1}{2} \) x \( \Large \frac{D}{5x} \)
10D - 560 = 3D
7D = 560
D = 80
\( \Large \frac{D - 32}{3x} \) = 4
80 - 32 = 12x
x = \( \Large \frac{48}{12} \)
x = 4
Speed of current = \( \Large \frac{5x - 3x}{2} \) = \( \Large \frac{2x}{2} \)
x = 4 km/h
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