Time taken by A alone to finish a piece of work is 60% more than that taken by A and B together to finish the same piece of work. C is twice as efficient as B. If B and C together can complete the same piece of work in 13 \( \Large \frac{1}{3} \) days, in how many days can A alone finish the same piece of work ?
Correct Answer: Description for Correct answer:
let the time taken by B = x days
Time taken by c = \( \Large \frac{x}{2} \) days
According to questions
\( \Large \frac{1}{x} \) + \( \Large \frac{2}{x} \) = \( \Large \frac{3}{40} \)
\( \Large \frac{3}{x} \) = \( \Large \frac{3}{40} \)
x = 40 days
Let the time taken by A = y days
y = \( \Large \frac{40y}{40 + y} \) x \( \Large \frac{160}{100} \)
40 + y = 64
y = 24 days
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