Man sold two ArticlesA (at a profit of 40%) and B (at a loss of 20%). He incurred a total profit of Rs 18/inthe whole deal. If Article A costs Rs 140/less than Article B. what is the price of article B ?
Correct Answer: Description for Correct answer:
Let the cost price of article B = Rs x
Cost price of article A = Rs(x - 140)
According to question,
(x - 140 ) x \( \Large \frac{140}{100} \) + x * \( \Large \frac{80}{100} \) = x + x - 140 + 18
\( \Large \frac{14x - 1960 + 8x}{10} \) = 2x - 122
22x - 1960 = 20x - 1220
2x = 740
x = Rs 370/-
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