f(x)=\( \Large \frac{1}{x^{2}} \) and g (x)=\( \Large e^{-9x} \) then (f o g) (x) is

A) \( \Large \frac{1}{e^{18x}} \)
B) \( \Large \frac{1}{e^{-18x}} \)

C) \( \Large \frac{1}{e^{-18x^{2}}} \)
D) \( \Large \frac{1}{e^{18x^{2}}} \)

Correct answer:
B) \( \Large \frac{1}{e^{-18x}} \)


Please provide the error details in above question

Recent Activities
Home About Us Terms and Conditions Privacy Policy Contact us