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A certain sum is divided among A, B and C in such a way that A gets Rs. 40 more than the \( \Large \frac{1}{2} \) of the sum, B gets Rs. 120 less than \( \Large \frac{3}{8} \)th of the sum and C gets Rs. 200. What is the total sum ?
A) Rs. 1100
B) Rs. 850
C) Rs. 960
D) Rs. 1200
Correct answer:
C) Rs. 960
Description for Correct answer:
Let initial amount be Rs. x
\( \Large \therefore A => \frac{x}{2} + 40 \)
\( \Large B => \frac{3x}{8} - 120 \)
\( \Large \therefore C's share \)
= \( \Large x - \frac{x}{2} - 40 - \frac{3x}{8} + 120 \)
= \( \Large x- \frac{x}{2} - \frac{3x}{8} + 80 \)
= \( \Large \frac{8x - 4x - 3x}{8} + 80 \)
= \( \Large \frac{x}{8} + 80 \)
According to the question,
\( \Large \frac{x}{8} + 80 = 200 \)
=> \( \Large \frac{x}{8} = 200 - 80 = 120 \)
=> \( \Large x = 120 \times 8 = 960 \)
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