In the following question two equations numbered I and II are given. You have to solve both the equations and -

I. \( \Large \frac{3}{\sqrt{x}} + \frac{4}{\sqrt{x}} \) = \( \Large \sqrt{x} \)

II. \( \Large y^{3} - \frac{(7)^{\frac{7}{2}}}{\sqrt{y}} \) = 0

A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x = y or the relationship cannot be established

Correct answer:
D) x = y or the relationship cannot be established

Description for Correct answer:
I. \( \Large \frac{3}{\sqrt{x}} + \frac{4}{\sqrt{x}} = \sqrt{x} \)

=> 3 + 4 = x

=> x = 7

II. \( \Large y^{3} - \frac{(7)^{\frac{7}{2}}}{\sqrt{y}} = 0 \)

\( \Large y^{3 + \frac{1}{2}} - (7)^{\frac{7}{2}} \) = 0

=> \( \Large y^{\frac{7}{2}} = 7^{\frac{7}{2}} \)

=> y = 7

Please provide the error details in above question

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