In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer

I.\( \Large 2x^{2} \) + 11x + 14 = 0

II.\( \Large 4y^{2} \) + 12y + 9 = 0

A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x \( \Large \leq \) y

Correct answer:
C) x < y

Description for Correct answer:
\( \Large 2x^{2} \) + 7x + 4x + 14 = 0

=> x ( 2x + 7 ) + 2 ( 2x + 7 ) = 0

=> ( x + 2 )( 2x + 7 ) = 0

=> x = -2 or -\( \Large \frac{7}{2} \)

II. 4\( \Large y^{2} \) + 2.2y.3 + 9 = 0

=> \( \Large ( 2y + 3 )^{2} \) = 0

=> 2y + 3 = 0

\( \Large \therefore y = -\frac{3}{2} \)

Clearly, x < y

Please provide the error details in above question

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