Description for Correct answer:
I. 2x + 3y = 4

II. 3x + 2y = 11

Multiplying equation I by 3 and equation II by 2 and subtracting equation II from equation I

\( \Large 6x + 9y = 22 \) -- (1)
\( \Large 6x + 4y = 22 \) -- (2)
(1) - (2)
=> 5y = -10

\( \Large \therefore \) y = -2

Putting the value of y = -2 in equation I,

2x + 3 \( \Large \times \) -2 = 4

=> 2x = 6 + 4

=> x = \( \Large \frac{10}{2} \) = 5

Clearly, x > y