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If three unbiased coins are tossed simultaneously, then the probability of exactly two heads, is
A) 1 / 8
B) 2 / 8
C) 3 / 8
D) 4 / 8
Correct answer:
C) 3 / 8
Description for Correct answer:
n(S) = \( 2^3 \) = 8
Let E = Event of getting exactly two heads
= {(H,H,T),(H,T,H),(T,H,H)}
=n(E) = 3
Required probability = 3 / 8
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