Any positive or negative number \(  \Large  \neq \) 0 will never have its square as zero or negative

If k = \( \Large \frac{1}{2} \)
Then \(  \Large  k^2 \) = \( \frac{1}{4}\)

So \(  \Large  k^2 < k \)
Hence \(  \Large  k^2 < k \) is true.