Description for Correct answer:
\( \Large \frac{ \left(a^{3}+b^{3}\right) \left(a^{2}+b^{2}\right) }{ \left(a^{2}-ab+b^{2}\right) \left(a-b\right) } = \frac{ \left(a+b\right) \left(a^{2}-ab+b^{2}\right) \left(a+b\right) \left(a-b\right) }{ \left(a^{2}-ab+b^{2}\right) \left(a-b\right) } \)

=\( \Large \left(a+b\right) \left(a+b\right) = \left(a+b\right)^{2} \)