Description for Correct answer:
We know that,

\( \Large \left(a+b+c\right)^{2}= \left(a^{2}+b^{2}+c^{2}\right)+2 \left(ab+bc+ca\right) \)

=>\( \Large 196=96+2 \left(ab+bc+ca\right) \)

=>\( \Large 2 \left(ab+bc+ca\right)=196-96=100 \)

Therefore, \( \Large \left(ab+bc+ca\right)=\frac{100}{2}=50 \)