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If \( \Large a^{2}+b^{2}=234\ and\ ab=108 \), value of \( \Large \frac{a+b}{a-b} \)
A) 10
B) 8
C) 5
D) 4
Correct answer:
C) 5
Description for Correct answer:
We know that, \( \Large \left(a+b\right)^{2}=a^{2}+b^{2}+2ab \)
=\( \Large 234+2 \times 108=450 \)
\( \Large \left(a-b\right)^{2}=a^{2}+b^{2}-2ab \)
=\( \Large 234-2 \times 108=18 \)
Therefore, \( \Large \frac{ \left(a+b\right)^{2} }{ \left(a-b\right)^{2} }=\frac{450}{18}=25 => \left(\frac{a+b}{a-b}\right)^{2}=25 \)
Therefore, \( \Large \frac{a+b}{a-b}=\sqrt{25}=5 \)
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