The square of the length of the tangent from \( \Large \left(3,\ -4\right) \) to the circle \( \Large x^{2}+y^{2}-4x-6y+3=0 \) is:

A) 20

B) 30

C) 40

D) 50

Correct answer:
C) 40

Description for Correct answer:

Length of tangent from the point \( \Large  \left(x_{1},y_{1}\right)  \) to the circle \( \Large x^{2} + y^{2} +2gx + 2fy + c = 0  \) is 

\( \Large \sqrt{x_{1}^{2} +y_{1}^{2} + 2gx_{1} + 2fy_{1} + c  } \)
Required length of tangent from the point (3,-4) to the circle \( \Large x^{2} + y^{2} -4x -6y + 3 = 0 \)

\( \Large \sqrt{3^{2} + 4^{2} + -4(3) - 6(-4) + 3} = \sqrt{40}\)
Square of the length of tangenet is 40



Please provide the error details in above question