The equation of the straight line which is perpendicular to\( \Large y = x \) and passes through (3, 2) is:

A) \( \Large x-y = 5 \)
B) \( \Large x+y = 5 \)

C) \( \Large x+y = 1 \)
D) \( \Large x-y = 1 \)

Correct answer:
B) \( \Large x+y = 5 \)

Description for Correct answer:
Because, Slope of given line y = x is 1

Therefore, Slope of required line which is perpendicular to given line is -1

Thus, the equation of required 1 line passing through \( \Large \left(3,\ 2\right) \) and slop -1 is

\( \Large y-2 = -1 \left(x-3\right) => x+y=5 \)

Please provide the error details in above question

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