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The coefficient of x in the equation \( \Large x^{2}+px+q=0 \) was taken as 17 in place of 13 its roots Were found to be -2 and -15. The roots of the original equation are:
A) 3,10
B) -3 , -10
C) -5, -8
D) None of these
Correct answer:
B) -3 , -10
Description for Correct answer:
Let the equation (incorrectly written form)
be \( \Large x^{2}+17x+q=0 \)
since, roots are -2, -15
Therefore, q = 30
so, correct equation is \( \Large x^{2}+13x+30=0 \)
=> \( \Large x^{2}+10x+3x+30=0 \)
=> \( \Large \left(x+3\right) \left(x+10\right)=0 \)
=> x = -3, -10
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