Perimeter of first square = 12 cm. Therefor, Its side = \( \Large \frac{12}{4}=3\ cm \) Therefore, Its area = \( \Large 3^{2} = 9\ sq.cm. \) Perimeter of second square = 16 cm Therefore, Its side = \( \Large \frac{16}{4} = 4\ cm \) Therefore, Its area = \( \Large 4^{2} = 16\ sq.cm. \) Therefore, Area of new square = 9 + 16 = 25 sq. cm Its side = \( \Large \sqrt{25} = 5\ cm \)
