Let original radius be r.

Then, according to the question,

\( \Large \pi (r+1)^{2}-\pi r^{2} \)=22

=> \( \Large \pi\times [(r+1)^{2}-r^{2}] \)=22

=> \( \Large \frac{22}{7}\times (r+1+r)(r+1-r) \)=22

=> 2r+1=7 => 2r=6

r=\( \Large \frac{6}{2} \)=3 cm