We know that, area of segment (PRQP) = Area of sector (OPRQO)- Area of \( \Large \triangle OPQ\)

=\( \Large \frac{\pi r^{2}\theta}{360}-\frac{1}{2}r^{2}sin\theta \)
 

so, the area of a segment of a circle is always less than area of its corresponding sector.

II. Distance travelled by a circular wheel of diameter 2d cm in one revolution

= \( \Large 2\times 3.14\times d \)=6.28d

which is greater than 6d cm.