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The ratio of the length of the parallel sides of a trapezium is 3 : 2. The shortest distance between them is 15 cm. If the area of the trapezium is 450 sq cm, find the sum of the lengths of the parallel sides.
A) 15 cm
B) 36 cm
C) 42 cm
D) 60 cm
Correct answer:
D) 60 cm
Description for Correct answer:
Let the lengths of parallel sides an 3x and 2x.
We know that,
Area of trapezium = \( \Large \frac{1}{2} \) \( \Large (Sum \ of \ the \ parallel \ sides)\times Distance \ between \ them \)
\( \Large \frac{1}{2}(3x+2x)15=450 \)=>75x=900
x=\( \Large \frac{900}{75} \)=12 cm
Sum of the parallel sides = (3x + 2x)
= 5x = \( \Large 5\times 12 \)=60 cm
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