\( \Large x^{2}-16=0; y^{2}-9y+20=0 \)

A) If x>y

B) \( \Large If \ x\ge y \)

C) lf x

D) \( \Large If \ x \le y \)

Correct answer:
D) \( \Large If \ x \le y \)

Description for Correct answer:

\( \Large x^{2} - 16 = 0 \)

=> \( \Large x^{2} = 16 = x = \sqrt{16} = \pm 4 \)

and \( \Large y^{2} - 9y + 20 = 0 \)

\( \Large y^{2} - 4y - 5y + 2 = 0 \)

=> \( \Large y \left(y-4\right) - 5 \left(y-4\right) = 0 \)

=> y = 5, 4

\( \Large y \ge \  x \  or \  x \le y \)



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