Given, one roots of \( \Large x^{2}-6kx+5=0 \  is \  5 \)

Therefore, x = 5 satisfies \( \Large x^{2}-6kx+5=0 \)

= \( \Large 5^{2}-6 \times k \times 5+5=0 \)

= \( \Large 25-30k+5=0 \)

=> 30 - 30k = 0

=> 30k = 30

Therefore, k = 1