Description for Correct answer:
Let the cost of one chair be Rs. x

and cost of one table be y.

By given condition,

10x + 6y = 6200 ...(i)

and 3x + 2y = 1900

= 9x + 6y = 5700 ...(ii)

On subtracting Eq. (ii) from Eq. (i), we get

x = Rs.500

From Eq. (i),

5000 + 6y = 6200

= 6y = 1200

Therefore, y = Rs.200

The cost of 4 chairs and 5 tables

= 4x + 5y

= \( \Large 4 \times 500 + 5 \times 200 \)

= 2000 + 1000 = Rs.3000