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Find the area of a triangle whose sides measure 8 cm, 10 cm and 12 cm.

Correct Answer:

A) \( \Large 8\sqrt{63} \)sq cm |

B) \( \Large 5\sqrt{63} \)sq cm |

C) \( \Large 6\sqrt{53} \)sq cm |

D) \( \Large 7\sqrt{93} \)sq cm |

Correct Answer:

B) \( \Large 5\sqrt{63} \)sq cm |

Description for Correct answer:

Given that,

a=8cm, b = 10 cm and c=12cm

We know, that

s = \( \Large \frac{a+b+c}{2} \) = \( \Large \frac{8+10+12}{2} \)

= \( \Large \frac{30}{2} \)=15cm

(s-a)=(15-8)=7cm

(s-b)=(15-10)=5cm

(s-c)=(15-12)=3cm

Area = \( \Large \sqrt{s(s-a)(s-b)(s-c)} \)

= \( \Large \sqrt{15\times 7\times 5\times 3} \)= \( \Large \sqrt{1575} \)= \( \Large \sqrt{25\times 63} \)

= \( \Large 5\sqrt{63} \)sq cm.

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