The area of a right angled triangle is 40 sq cm. If its base is equal to 28 cm. find its height
 A) $$\Large 3\frac{6}{7}$$cm B) $$\Large 4\frac{6}{7}$$cm C) $$\Large 2\frac{6}{7}$$cm D) $$\Large 5\frac{6}{7}$$cm

 C) $$\Large 2\frac{6}{7}$$cm

Given that, area = 40 sq cm. base = 28 cm and height = perpendicular = ?

Area = $$\Large \frac{1}{2}\times Base\times Perpendicular$$

=> 40 = $$\Large \frac{1}{2}\times 28\times Perpendicular$$

Perpendicular =$$\Large \frac{40}{14}=\frac{20}{7}$$

=$$\Large 2\frac{6}{7}$$cm

Similar Questions
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