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The area of a right angled triangle is 40 sq cm. If its base is equal to 28 cm. find its height

Correct Answer:

A) \( \Large 3\frac{6}{7} \)cm |

B) \( \Large 4\frac{6}{7} \)cm |

C) \( \Large 2\frac{6}{7} \)cm |

D) \( \Large 5\frac{6}{7} \)cm |

Correct Answer:

C) \( \Large 2\frac{6}{7} \)cm |

Description for Correct answer:

Given that, area = 40 sq cm. base = 28 cm and height = perpendicular = ?

Area = \( \Large \frac{1}{2}\times Base\times Perpendicular \)

=> 40 = \( \Large \frac{1}{2}\times 28\times Perpendicular \)

Perpendicular =\( \Large \frac{40}{14}=\frac{20}{7} \)

=\( \Large 2\frac{6}{7} \)cm

Given that, area = 40 sq cm. base = 28 cm and height = perpendicular = ?

Area = \( \Large \frac{1}{2}\times Base\times Perpendicular \)

=> 40 = \( \Large \frac{1}{2}\times 28\times Perpendicular \)

Perpendicular =\( \Large \frac{40}{14}=\frac{20}{7} \)

=\( \Large 2\frac{6}{7} \)cm

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