A) 5 s |
B) 6 s |
C) 7 s |
D) 8 s |
B) 6 s |
Total length of the train =105+ 90 = 195m
Relative speed = 72 + 45 km/h
= \( \Large \left(117 \times \frac{5}{18}\right) = \frac{585}{18} m/s \)
Therefore, Required time = \( \Large \left(195 \times \frac{18}{585}\right) \) = 6 s