A) 100 m |
B) 115 m |
C) 125 m |
D) 150 m |
C) 125 m |
Let length of each train be x m.
Then, \( \Large \left(65+85\right) \times \frac{5}{18} = \frac{x+x}{6} \)
\( \Large \frac{150 \times 5 \times 6}{18} = 2x \)
=> 2x = 250
Therefore, x = 125 m