A) 110 km |
B) 115 km |
C) 105 km |
D) 100 km |
C) 105 km |
Average speed or train = \( \Large \frac{240}{12} \) = 20 km/h
Average speed of bus
=> \( \Large \frac{3}{4} \times 20 = 3 \times 5 \) =15 km/h
Required distance = \( \Large 15 \times 7 \) = 105 km