A) 126 km |
B) 81 km |
C) 48 km |
D) 36 km |
B) 81 km |
If the trains meet after t h.
Relative speed of train = (24-18) = 6 km/h
= Distance = 27
Therefore, t = \( \Large \frac{27}{6} \) = \( \Large \frac{9}{2} \) h
Therefore, QR distance travel by train which is travelling at a speed of 18 km/h
=> 18t = \( \Large 18 \times \frac{9}{2} \)
= 81 km.