A) 3.2 m/s |
B) 1.4 m/s |
C) 2.8 m/s |
D) Cannot be determined |
C) 2.8 m/s |
Length of the train = 280 m
Length of the platform = 280 x 3 = 840 m
Taken time = 6 min 40 s
=> (360 + 40) 5 =400 s
Therefore, Required speed = \( \Large \frac{Distance}{Time} \)
= \( \Large \frac{840+280}{400} = \frac{1120}{400} \) = 28 m/s