A) 23 s |
B) 12 s |
C) 6 s |
D) 30 s |
C) 6 s |
Required time = \( \Large \frac{Distance \ covered \ by \ train}{Relative \ speed \ of \ train} \)
\( \Large \frac{180+120}{ \left(72+108\right) \times \frac{5}{18} } \)
\( \Large \frac{300 \times 18}{180 \times 5} \) = 6 s.