A) 225 m |
B) 200 m |
C) 135 m |
D) 90 m |
A) 225 m |
Let the length of the train be x m.
According to the question,
\( \Large \frac{x}{9}=Speed \) ...(i)
\( \Large \frac{x+150}{15}=Speed \) ...(ii)
From Eqs. (i) and (ii), we get
\( \Large \frac{x}{9} = \frac{x+150}{15} \)
=> \( \Large \frac{x}{3} = \frac{x+150}{5} \)
=> 5x = 3x + 450
=> x = 225 m