A) 420 m |
B) 500 m |
C) 300 m |
D) 250 m |
C) 300 m |
Speed of train = 60 km/h
= \( \Large 60 \times \frac{5}{18} m/s = \frac{50}{3} m/s \)
Let length of the platform be x m.
According to the question,
200 + x = \( \Large \frac{50}{3} \times 30 \)
= 200 + x = 500
Therefore, x = 300 m