A basket contains three blue and four red balls. If three balls are drawn at random from the basket, what is the probability that all the three balls are either blue or red?
Correct Answer: Description for Correct answer:
Probability to be blue = \( \large\frac{3C_3}{7C_3} \)
Probability to be Red = \( \large\frac{4C_3}{7C_3} \)
Required probability = \( \large\frac{3C_3}{7C_3} + \frac{4C_3}{7C_3} = \frac{5}{35} = \frac{1}{7}\)
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