A basket contains 4 red, 5 blue and 3 green marbles. If two marbles are drawn at random, what is the probability that both are red?
Correct Answer: Description for Correct answer:
Total number of possible outcomes
= n(S) = \( 12C_2 = \frac{12 X 11 }{2} = 66 \)
Total number of favourable events
= n(E) = \( 4C_2 \)
=\( \large\frac{4 \times 3}{2 \times 1} = 6 \)
Required probability = \( \large\frac{6}{66} = \frac{1}{11} \)
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